Algebraic structures provide a unified mathematical framework for studying sets equipped with operations that combine elements. This curriculum covers the progressive building blocks of abstract algebra, progressing from basic binary operations to semigroups, monoids, groups, and subgroups.
To establish these algebraic structures, we begin with foundational sets:
A binary operation on a non-empty set is a function . We say that the operation is closed on if:
An algebraic system (or algebraic structure) is a non-empty set together with one or more binary operations defined on it. It is formally written as an ordered tuple:
The hierarchy of algebraic structures based on the algebraic properties they satisfy is structured as follows:
Algebraic Systems (Set + Binary Operation)
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Semigroups (Closed + Associative)
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Monoids (Semigroup + Identity)
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Groups (Monoid + Inverses)
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Abelian Groups (Group + Commutative)Let be a binary operation defined on a set .
The operation is commutative in if the order of operands does not affect the output:
The operation is associative in if the grouping of operations does not alter the final result:
For an algebraic system , an element is called the identity element of if:
Theorem: If an identity element exists in an algebraic system , it is unique.
Proof: Assume and are two distinct identity elements in . Since is an identity:
Let be an algebraic system with unique identity . An element is said to be the inverse of if:
We denote the inverse of as .
We can now classify algebraic structures by layering these properties.
An algebraic system is a semigroup if it satisfies the following two axioms:
Consider a semigroup and let . The system is a subsemigroup of if is closed under the operation :
If and are semigroups, then their Cartesian product is a semigroup under the component-wise operation defined by:
Proof:
Closure: Since is closed under , . Since is closed under , . Thus, .
An algebraic system is a monoid if it satisfies three axioms:
Let be a monoid with identity element . A subset is a submonoid of if and only if:
Let . Let be a unary operation on given by:
The element acts as a generator of the algebra. By repeatedly applying the unary operator starting from , we can generate the entire set :
1 ──T──► 2 ──T──► 3 ──T──► ... ──T──► m ──T──► 1Let , and let be defined by the set of ordered pairs:
We can form composite functions by composing with itself:
The collection of functions under the binary operation of function composition forms an algebraic system .
An algebraic system is a group if it satisfies the following four conditions:
A group is called Abelian (or commutative) if the operation satisfies the commutative law:
Show that is an Abelian group.
Hence, is an Abelian group.
Let be the set of all non-zero real numbers.
Hence, is an Abelian group.
Note: The entire set of real numbers under multiplication is not a group because the element has no multiplicative inverse ( is undefined).
Let (positive rational numbers) and let be defined by .
Closure: Since are positive rationals, is also a positive rational.
Associativity:
Hence, is an Abelian group.
For any group , the following fundamental properties hold:
The inverse of any element is unique.
Proof: Let and be two inverse elements of . By the definition of an inverse:
Since , we apply the left cancellation law (multiplying by the inverse of on the left):
In any group , left and right cancellation laws hold:
Proof (Left Cancellation): Since is a group, exists for all .
For any , .
Proof: Let us compute the product of and :
If every element of a group is its own inverse (i.e., for all ), then must be Abelian.
Proof: Let . Since every element is its own inverse, we have:
In a group , if for all , then is an Abelian group.
Proof: Note that . Given:
The order of a group , denoted by or , is the number of elements in the set . If the order is finite, the group is called a finite group. We can visualize finite groups using Cayley Tables (composition tables).
The composition table is:
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Here, and . The composition table under multiplication is:
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The composition table under multiplication () is:
| | | | | | | :--- | :--- | :--- | :--- | :--- | | | | | | | | | | | | | | | | | | | | | | | | |
Modulo operations offer a way to construct finite groups over integers.
For a positive integer and any :
This represents the remainder () obtained when is divided by .
For a positive integer and any :
This represents the remainder () obtained when the product is divided by .
Let under .
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Let under multiplication modulo .
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General Modulo Rules:
- The set forms an Abelian group under addition modulo .
- The set forms an Abelian group under multiplication modulo if and only if is a .
Let be a group. A non-empty subset is called a subgroup of if itself forms a group.
A non-empty subset of a group is a subgroup of if and only if:
Proof:
Direct Direction: If is a subgroup, it forms a group under . Since , its inverse . Since is closed under , and .
Let be an element of a group . The order of is the smallest positive integer such that:
If no such finite integer exists, the element is said to have infinite order.
Let and be two groups. A function is called a if it preserves the group operation:
G (with operation *) G' (with operation ⊕)
┌──────────────────────┐ ┌──────────────────────┐
│ a , b │ f │ f(a) , f(b) │
│ ├────────►│ │
│ a * b │ │ f(a) ⊕ f(b) │
└──────────────────────┘ └──────────────────────┘
▲ ▲
└────────── preserves ───────────┘If a homomorphism is also a bijection (both one-to-one and onto), then is called an isomorphism. Under these conditions, the groups and are structurally identical, denoted as .
A rule combining two elements of a set to produce another element of the same set, strictly satisfying the closure property.
A semigroup is a set closed under an associative binary operation; a monoid is a semigroup containing an identity element.
A monoid where every element possesses a unique inverse, guaranteeing that equations within the system have unique solutions.
A group whose binary operation also satisfies the commutative property, allowing elements to be reordered without changing the output.
A non-empty subset of a group that constitutes a group in its own right under the induced binary operation.
Test your understanding with 5 questions
In the multiplicative group $G = \{1, -1, i, -i\}$, what is the order of the element $-i$?
If $(G, *)$ is a group and there exists an element $a \in G$ such that $a * a = a$, which of the following must be true?
Let $(A, *)$ be an algebraic system where $A = \{1, 3, 5, 7, 9, \dots\}$ is the set of positive odd integers, and $*$ represents standard multiplication. What is the algebraic classification of $(A, *)$?
Under what conditions does the set $G = \{1, 2, 3, \dots, n-1\}$ form a group under the operation of multiplication modulo $n$?
Let $H$ be a non-empty subset of a group $(G, *)$. Which of the following is the single-step necessary and sufficient condition for $H$ to be a subgroup of $G$?
Since is also an identity:
Equating the two expressions gives . Thus, the identity element is unique.
Associativity: Let .
Since is closed and associative, is a semigroup.
Thus, associativity holds.
Identity: Let be the identity. We must have :
Since , the identity element is .
Inverse: Let be the inverse of . We must have :
Since is rational, . Every element has an inverse.
Commutativity: .
Thus, the inverse of any element is unique.
Similarly, . By the uniqueness of the inverse, .
Applying the Socks-and-Shoes property to :
Since for all , the group is Abelian.
By associativity, we can regroup the terms:
Applying Left Cancellation (eliminating on the left):
Applying Right Cancellation (eliminating on the right):
Thus, is Abelian.
Converse Direction: Assume for all .
Identity Element: Since is non-empty, we can pick some element . Letting and , we have:
The identity element is in .
Inverse Element: Let and (where ). Then:
Closure: Let . Since , we know its inverse . Now let and .
Associativity: Since , associativity is inherited from .
Since satisfies all four group axioms, is a subgroup.
6 Modules
6 Modules
Every element in has its inverse in .
Thus, is closed under .